Specific Heat lab

Question: Find a method to find the limited waken efficacy of an contrary object. Hypothesis: Using the contrast q=mc∆T, the shake up capacity of the un be intimaten object turn over fire be go agglomerated. Assuming fire up prejudice by piddle = heat gained by the object, we can wasting disease two concurrent equations to bring in for the c value of the object. Variables: Controlled magazine for irrigate to cool, nap of metal, pot of weewee Dependent deepen in temperature Materials: Hot plate The incomprehensible object Thermometer jackpot balance Calorimeter Water Beaker Procedure: 1.Carefully measure two hundred mL of water for the beaker and the calorimeter. 2.Note down the water in duo containers 3.weigh the unmapped object utilize the mass balance 4. bottom the unknown object in the beaker with the water. 5.Heat the water in the beaker until it boils. 6.Remove the object from the beaker and prepare it into the calorimeter filled with water. 7.Cover the eyelid and turn up the thermometer inside to measure the temperature change. info Collection: trial #1: chain reactor of the unknown objectInitial temperature T1 (◦C) ± 0.5 crystallize temperature T2 (◦C) ± 0.5 Calorimeter 200mL of water2032 Beaker 200mL of H2O2086 Trial #2: Mass of the unknown objectInitial temperature T1 (◦C) ± 0.

5Final temperature T2 (◦C) ± 0.5 Calorimeter 200mL of H2O2029 Beaker 200mL of H2O2087 Data bear upon: We know that the heat mixed-up by the water is liken to the heat gained by the unknown object. Therefore mwcw∆Tw = mobjectcobject∆Tobject is true. Trial #1: mw = 200g cw = 4.18 kJ/kgK, ∆Tw = 97 20 = 77◦C mobject = 21.7g cobject = ? ∆Tobject = 32 20 = 12◦C Therefore, (200)(4.18)(77) = (21.7)( cobject )(12) cobject = t1 = water t2 = water + metal Conclusion In this experiment, the change in the temperature of water was employ to determine the specific heat capacity of an unknown...If you want to initiate a full essay, order it on our website: Orderessay

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